If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2+7x+12=10x+52
We move all terms to the left:
x^2+7x+12-(10x+52)=0
We get rid of parentheses
x^2+7x-10x-52+12=0
We add all the numbers together, and all the variables
x^2-3x-40=0
a = 1; b = -3; c = -40;
Δ = b2-4ac
Δ = -32-4·1·(-40)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-13}{2*1}=\frac{-10}{2} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+13}{2*1}=\frac{16}{2} =8 $
| 4a-3=2(a-6) | | 1/2-11n=-25 | | |10v+4|=84 | | -1/2n-11=-25 | | 3(x−4)=12 | | 12t+24=(-36) | | 24=-3(x-2)=3 | | 7p-(3p+4)=-1)10 | | -2y=-2y+16 | | 5x+14-4x=6x+10-2x | | 3x+11=16- | | X2-8x+3=0 | | d/3-7=4 | | -g+2(3+g)=-4(8+1) | | 16=2w-4 | | 2p-3=5-2p* | | 130-4x=x | | 31=r/4+2 | | 6-(2x+3)=x+12 | | 4g−124,g=5 | | -g+-4=-9 | | 19×x=21 | | 3/2=15/z | | 9h+4=45 | | q/2+20=16 | | -5=q−9q= | | 3(-9+7x)=57 | | 4(x-9)=-36+4x= | | 17=3g−-8 | | -5=q−9 | | 7=n+20 | | m*10=4 |